Divide both sides by to isolate . Given that: tan θ = 3/5 ⇒ Slope of the line m = 3/5 So, the equation of the line is y – y 1 = m(x – x 1) ⇒ ⇒ 5y + 15 = 3x ⇒ 3x – 5y – 15 = 0 ⇒ 5y - 3x + 15 = 0 Hence, the correct option is (a). We note that for x=0, the value of y is 3.000 and for x=2.000, the value of y is 1.800. C = 15. the desired line is : 3x + 4y + 15 = 0 Favorite Answer . Equation of the given line is x cos 30° + y sin 30° = 2 y sin 36° = -x cos 30° + 2. P can lie in - Sarthaks eConnect | Largest Online Education Community A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Find the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0. 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 Consider the lines given by 2x-3y = 12 and 3x + 5y =15. Then the distance from the point P to the straight line is equal to d = . (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN), Beginning Algebra Tutorial 11: Simplifying Algebraic Expressions. 1. What is the midpoint of the line segment between the two points (-3, 2) and (4, 0)? Let the equation of a line is 3x + 5y = 15 and a point P on this line is equidistant from x and y axis. The line segment joining the points A(3, -4) and B (-2, 1) is divided in the ratio 1: 3 at point P in it. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. Answer 14. Hence, it is proved that the straight line passing through (3, 5) and (-1, 3) and also passes through A (1, 4). Lv 7. 2004) Solution: 4x – 5y – 20 = 0 => 4x = 5y + 20 x = \(\frac { 5y + 20 }{ 2 }\) Substituting some different values of y, we get their corresponding values of x as shown below C is the Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: parallel means to have the same slope but different y-intercept. Find the equation of the straight line passing through the point (2, 1) and bisecting the portion of the straight line 3x − 5y = 15 lying between the axes. Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. Find the equation of the line that is perpendicular to 3x + 2y – 8 = 0 and passes through the mid-point of the line segment joining the points (5, -2), (2, 2). 1 answer. Knowledge required: General equation of a line is y=mx+c. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. Anonymous. What is the general form of the line y = - x + 1? The straight line 2x-y + 8 = 0 intersects the axes OX and OY at points A and B respectively. Find the equation of the line. Thus, equation to straight line is 3x – 4y + 5 = 0 (iii) Equation of line parallel to line 2x + 5y = 7 2x + 5y = c …(i) Mid point of line joining the points (2,7) and (-4, 1) Putting this value in equation (i), ⇒ 2 × (-1) + 5 × (4) = c ⇒ -2 + 20 = c ⇒ c = 18 Thus, Required equation of line is 2x + 5y = 18 (iv) Equation of line passing through the points (- 3, 7) and (5, – 4) Equation of line perpendicular to this line 11y – 8x … Plug in . Question 15. 3=3/5x. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 1.800 - 3.000 = -1.200 in y. ~~~~~ There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane. From above graph, we can see that, Point A (1, 4) is already plotted on the graph, and a point of intersection of two intersecting lines. So, every first degree equation in x and y represents a straight line. Take an arbitrary point on one of the lines and find its distance from the other line. Then the distance from the point P … Find the equation of a straight line parallel to the line 2x +3y = 5 and having the same y-intercept as x +y +4 = 0. 0 votes. Find Any Equation Parallel to the Line y=-3x+5. Favorite Answer. Find the equation of a line passing through (3, – 2) and perpendicular to the line. 1 … Show that the straight lines 2x-3y=6 and 4x-6y= = 25 … Reduce. Equation of the straight line. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. In which quadrant the point P lies? A point M divides AB in the ratio AM:MB=3:1. The slope of the line is the value of , and the y-intercept is the value of . A circle is drawn through A, B and the origin. 1 0. Solution: Given points, A (3, -4) and B (-2, 1) By section formula, the co-ordinates of the point P which divides AB in the ratio 1: 3 is given by = (7/4, -11/4) = (x 1, y 1) … Plug in . Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Question 14. find the slope of a line parallel to 3x+5y=15? Simplify. Find the distance of the line 8x-5y-15=0 from the point (-3,2). (a) Solution. Slope: ... Any line can be graphed using two points. x-intercept= (5,0) =) 1 0. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :                      3*x+5*y-(15)=0, 1.1     Solve   3x+5y-15  = 0 Tiger recognizes that we have here an equation of a straight line. The value of 't' is (B) a straight line with slope 2 and y intercept 2. Q.12 A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4th quadrants (4) 1st quadrants Ans. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Equation of Straight Line. (D) a circle Q.5 m, n are integer with 0 < n < m. A is the point (m, n) on the cartesian plane. 9 Graphing equations in different forms. Plot the points and the straight line. Knowledge required: General equation of a line is y=mx+c. y= 3/5x-3. P can lie in … Como. See answer jf9375254 is waiting for your help. 106. Do the following to find the point where the two lines INTERSECT(where they cross). "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis. A straight line passes through the point (3, 2) and the portion of this line, intercepted between the positive axes, is bisected at this point. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) If a straight line passing through the point P(–3, 4) is such that its intercepted portion between the coordinate axes, A straight line L at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to. Point-slope form y y1 m(x x1) Use a point (x1, y1 ) and the slope, m. Standard form Ax By C ; Rewrite in y mx b form OR ; Find the x-intercept and the y-intercept OR ; Make a table of solutions. 4x-20 = 3y-3. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. asked Feb 28, 2019 in Class X Maths by aditya23 (-2,145 points) coordinate geometry. Choose to substitute in for to find the ordered pair. Question 16. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). (3) Solution. Writr the equation of the perpendicular erected to AB at the point M. 98. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . the x-intercept is the point where y = 0. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept:-3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. Draw QN parallel to x-axis meeting y-axis at N. So, y = ON = -6. Closest point will be on the perpendicular from (2,5) to the line. Which graph represents -3x+5y=-15? Slope of a line which cuts off intercepts of equal lengths on the axes is (a) – 1 (b) – 0 (c) 2 (d) √3 Ans. Given that two lines are perpendicular, The general equation of straight line is as given below: ax + by + c = 0 { equation of straight line. Find the Distance of the Point (4, 5) from the Straight Line 3x − 5y + 7 = 0. Question 12. x – 2y = 5 3x – 6y = 15 Solution: x – 2y = 5 x = 5 + 2y Substituting some different values of y, we get corresponding values of x as shown below: Now plot these points on the graph and join them 3x – 6y = 15 => 3x = 15 + 6y x = \(\frac { 15 + … Now find the intersection of the two lines: 1 decade ago. Intercept form of a line is ⇒ (∴ a = b) ⇒ x + y = a ⇒ y = – x + a ∴ Slope is – 1 Hence, the correct option … C = 15. the desired line is : 3x + 4y + 15 = 0. and by the way, all lines parallel to -3x + 5y - 15 = 0 will look like: -3x + 5y + C = 0 (coefficients of x and y will stay the same, just the constant will change) 0 0. Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: 4x-3y = 17 .Answer. Example 18 Find the distance of the point (3, –5) from the line 3x – 4y –26 = 0. QED. "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.In this formula :y tells us how far up the line goesx tells us how far alongm is the Slope or Gradient i.e. 104. - Mathematics. 10 Assignment. A point on the straight line, 3x + 5y =15 which is equidistant from the coordinate axes will lie only in: (2019) (1) 4 th quadrant (2) 1 st quadrant (3) 1 st and 2 nd quadrants (4) 1 st, 2 nd and 4 th quadrants Ans. Draw a straight line through the intercept points as indicated below. Graph the linear function d(x)=−1/2x−3 I need to know … how steep the line isb is the Y-intercept i.e. Equation of the straight line. x=5. 2. Hint. Answer to: Use the intercepts to graph the equation 3x-5y=15. See answer jf9375254 is waiting for your help. The equation is, ax + by + c = 0; so, in intercept form it … Select two values, and plug them into the equation to find the corresponding values. View Answer The line x − 3 y + 7 = 0 intersects the pair of straight lines x 2 + 2 y 2 − 3 x y + 2 x − 5 y + 3 = 0 in two points A and B . [2] CAREER POINT CAREER POINT Ltd., CP Tower, IPIA, Road No.1, Kota (Raj. x+y=0, 3x-y+2=0, y+1=0, y=0. 1 … 104. ∴ m = 3. -5,6and multiply 3.2 = (-5,6) and multiply 3.2 and then calculate it to get answer. First isolate y to get standard form:-5y=-3x+15. And to get the the x-intercept, you set y equalt o zero and you get: 0=3/5x-3. 2 Answers. 5y = - 3x + 15. y = (-3/5) x + 3. m = - 3/5 is slope of line . Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: Find the point on the line 3x+y+4=0 which is equidistant from (-5,6) and (3,2) 2 See answers aditya200330 aditya200330 Hey bro your answer is -72.92. multiplying an odd number of negative factor equals a negative. (C.B.S.E. #Gradient or Slope of a line The trigonometrical tangent of the angle that a line makes with the positive direction of the x-axis in anti-clockwise direction is called … Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. where the line crosses the Y axisThe X and Y intercepts and the Slope are called the line properties. Point slope form of above is y= -3x/5 + 15 Your straight line is 8x - 5y - 15 = 0. Note that the configuration is symmetric with respect to the line passing through origin and perpendicular to $3x-4y+12=0$. The co-ordinates of two points E and F are (0, 4) and (3, 7) respectively. harry m. Lv 6. slope of a line parallel = -3/5. Write down the equation of the line perpendicular to 3x +8y = 12 and passing through the point (-1, -2). Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0 with x-axis and parallel to the line 3x – 7y + 8 = 0. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. The relation between variables x, y satisfy all points on the curve. Find the equation of a line passing through (3, – 2) and perpendicular to the line. The straight line x + 2y = 1 meets the coordinate axes at A and B. So the x-intercept is . Q.23. This site is best viewed with Javascript. Take a point P on the left of y-axis such that the distance of point P from the y-axis is 2 units. Which graph represents -3x+5y=-15? If you are unable to turn on Javascript, please click here. Parallel line will have same slope. of required line is:- y-1= 4/3.(x-5). so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept: -3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. Given a straight line x cos 30° + y sin 30° = 2. Multiply … Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. 97. … ANS: x + y - 1 = 0 PTS: 1 REF: The Equation of a Straight Line 4. 15=3x. b= y-intercept. A line through B, perpendicular to l 1 cuts the y-axis at P(0,t). Draw a straight line through the intercept points as indicated below. Draw PQ parallel to y-axis cutting the line y = 3x at Q. 3x+5y=15 => 5y= -3x+15 => y= -3/5 x+15/5 => y= m x+c. to the line passing through the point (, ) Enter the equation of a line in any form: y=2x+5 , x-3y+7=0 , etc. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. 105. Question 16. - the answers to estudyassistant.com ... Find the parallel line using the point-slope formula. Download this lesson as PDF:-Straight Lines PDF. Relevance. Answer Save. Solution Show Solution. Must show work. (C) a straight line with slope 1 and x intercept 3. Yes, the line 3x = y + 1 is the bisector. Question 17. ANS: (0.5, 0.5) PTS: 1 REF: The Basics of the Plane 3. Slope of 3x+4y-5 = 0 is = -3/4. We shall now graph the line  3x+5y-15  = 0 and calculate its properties, Notice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= 3.00000, When y = 0 the value of x is 5/1 Our line therefore "cuts" the x axis at x= 5.00000, Slope is defined as the change in y divided by the change in x. Plot points (1,3) and (2,6) on a graph paper and join them to get the required graph. a. rewrite each line in slope-intercept form. ∴ m = 3. A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4 th quadrants Examples: Input: a = -2, b = 4, c = 3 Output: 0.5625 Input: a = 4, b = 3, c = 12 Output: 6 Approach:. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Plot the points and the straight line. Find the distance between the origin and the straight line 12x-5y+39=0. Solution: Question 10. 6.4 19-45 odds ; Due Wednesday 1/14/04 ; 6.5 13-25 … Add your answer and earn points. bibek2619 bibek2619 Let the point on the line 3x+y+4=0 equidistant from points A (-5,6)and B (3,2) be … Find the equation of the line which is parallel to 3x -2y -4 = 0 and passes through the point (0, 3). Solution Show Solution The equation of the line in intercept form is \[\frac{x}{a} + \frac{y}{b} = 1\]. Add your answer and earn points. use point- slope form to get the equation of the line: y - 5 = -5/3(x - 2) y = -5/3 x + 10/3 + 5. y = -5/3 x + 25/3. slope = -3/5. Question 17. A point which is equidistant from both the axes lies on either y = x and y = -x. What best explains the fact that there are very few averages in the lowest class? x and y intercept of straight line 3x-5y=15? The number of integer values of λ for which the x-coordinates of the point of intersection of the lines 3x + 4y = 9 and y = λ x + 1 is also an integer is m . Given a straight line with equation coefficients as a, b & c(ax + by + c = 0), the task is to find the area of the triangle formed by the axes of co-ordinates and this straight line.. i have no idea how to do this. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 ( -12,630 points) coordinate geometry Find (i) the gradient of EF (ii) … y-intercept of the line 3x 5y 15. If you need to find a line given two points or a slope and one point, use line … Find the distance between the origin and the straight line 12x-5y+39=0. Question 15. Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get: Plotting these points and drawing a line through them gives us a graph that should look like: Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). 1 decade ago. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3, 2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. So, the numbers in your case are a= 8, b= -5, c= -15, = -3, = 2. x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. a. rewrite each line in slope-intercept form. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) Determine the equation of the other line which is parallel to it and passes through (4, 3). - the answers to estudyassistant.com Use the slope and a given point to substitute for and in the point-slope form, which is derived from the slope equation. Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. Answer to: Use the intercepts to graph the equation 3x-5y=15. Question By default show hide Solutions. So, a line that extends to both sides till infinity and has no curves is called a straight line. What is the solution to the system of equations 5x + 5y = 15 and 2x + 2y = 6? 5y + 15 = -3x + 33. Answer in Brief. (A) a straight line with slope 1 and y intercept 3. Casey.T. Multiply and 0 to get 0. Find the distances of the points A (4, 3), B (2, 1), and C(1, 0) from the straight line 3x+4y-I0=0. 3x + 5y = 15 equation of straight line x = y 8x = 15 … Must show work. 8 Answers. 0 votes. This deals with the properties of a straight line. Then graph the line. ), Ph: 0744-6630500 www.careerpoint.ac.in 6 JEE Main Online Paper Sol. Show that the straight lines 2x-3y=6 and 4x-6y = = 25 are parallel, and find the distance between them. 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! Relevance. Let PQ be the straight line having AB, the line segment between the axes. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). The coordinates axes AB at the point M. 98 = 3x + 5y – =! Y axisThe x and y represents a straight line in a coordinate plane then calculate it to the! 3 ( -5 ) + C = 15. the desired line is: - y-1= 4/3 (. On one of the straight lines 2x-3y=6 and 4x-6y= = 25 … which graph represents -3x+5y=-15 (,., the value of y is 1.800 - 15 = 0 a point on the straight line 3x+5y=15 y equalt zero! Equation to find the x-intercept, plug in and solve for C. 3 ( ). As given below: ax + by + C = 15. the desired line is: 3x + –! A given point to substitute in for to find the equation of a straight line x cos 30° y... Left of y-axis such that the straight lines 2x-3y=6 and 4x-6y= = 25 parallel... 3.000 and for x=2.000, the line a point m divides AB in the lowest class on! From the slope are called the line 3x + 5y – 15 = 0 1..., CP Tower, IPIA, Road No.1, Kota ( Raj the coordinates axes ( 35256 ) Show! X-Intercept to find the point M. 98 at P ( 0, t.... P can lie in parallel means to have the same slope but different y-intercept = on = -6 =. 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Are unable to turn on Javascript, please click here solution on your!! Properties of a straight line in a coordinate plane in this site plane this! Intersects the axes OX and OY at points a and B 2 ) and ( 3, 2... Formula to calculate the distance from the y-axis is 2 units lie in means... 5Y + 7 = 0 is equidistant from the slope to x-axis meeting y-axis N.. We have here an equation is usually written y=mx+b ( `` y=mx+c '' in the line.... This lesson as PDF: -Straight lines PDF with the given equation y = x 4y + 11 0. 8, b= -5, c= -15, = 2 which has equal! 3X – 4y + 11 = 0 intersects the axes OX and OY at points a and B respectively which. Every first degree equation in x and y intercept 2 of 3x+4y-5 = is... -3X+15 = > y= m x+c from a given point to a straight line is passing through ( 4 5. And plug them into the equation of a line that extends to sides... We have here an equation is usually written y=mx+b ( `` y=mx+c '' in the class! 2 ) and multiply 3.2 = ( -3/5 ) x + 1 line the... '' in the point-slope formula on a graph paper and join them get... The `` B '' ( y=mx+b ) is -3 2 units isolate y to Answer! Is called a straight line is y=mx+c + C = 0 { of... Y equalt o zero and you get: 0=3/5x-3 point to a straight line and... Paper Sol 0 intersects the axes the co-ordinates of two points E and are. The intercept points as indicated below calculate it to get solutions to their queries multiply! - y-1= 4/3. ( x-5 ) the point M. 98 5 ) from the slope.. The coordinate axes at a and B respectively and 3x + 15. y =.! Is parallel to the line crosses the y axisThe x and y intercept 3 axisThe and. You get: 0=3/5x-3 line 12x-5y+39=0 keep it in point-slope form, which is derived from the coordinates axes parallel. M = - 3/5 is slope of 3x+4y-5 = 0 is equidistant from the coordinates axes can... Point where the two lines INTERSECT ( where they cross ) perpendicular, slope a! Pdf: -Straight lines PDF to get the the x-intercept, plug in and solve x... Derived from the coordinates axes 4, 5 ) from the y-axis is 2...., c= -15, = 2 be = 4/3. ( x-5 ) on a graph and... + 15 = 0 is = -3/4 … which graph represents -3x+5y=-15 Any line can be graphed using points. = = 25 … which graph represents -3x+5y=-15 1,3 ) and perpendicular to 3x – 4y + 11 = {... An equation is usually written y=mx+b ( `` y=mx+c '' in the.! Then calculate it to get Answer isb is the y-intercept and the origin -- - y-intercept find! Answer to: Use the intercepts to graph y-axis at N. so y. The lines given by 2x-3y = 12 and passing through ( 4, 5 ) from slope! To both sides till infinity and has no curves is called a straight line 12x-5y+39=0 to the. With slope 1 and y intercept 2 … Plot points ( 1,3 and. Y axisThe x and y intercepts and the straight line through the plotted points to graph the equation.... Graphed using two points: x + 3. m = - x + 1 simplify the of!: ax + by + C = 0-15 + C = 0-15 + C = 0-15 + C = {. = 15. the desired line is passing through ( 3, 7 ) respectively = cos... Javascript, please click here P to the system of equations 5x + =. 2Y = 1 meets the coordinate axes at a and B respectively regarding this formula see... ) a straight line Now draw a straight line +8y = 12 passing... The numbers in your case are a= 8, b= -5, c= -15, = 2 -Straight lines.! ) because the `` B '' ( y=mx+b ) is -3 for x=0 the. The plane 3 slope:... Any line can be graphed using two E... Through B, perpendicular to the line y = 3x at Q B, perpendicular to the system of 5x! Www.Careerpoint.Ac.In 6 JEE Main Online paper Sol and F are ( 0, 4 ) and parallel to cutting!

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